F(m)=2m^2+28m+100

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Solution for F(m)=2m^2+28m+100 equation: 



(F)=2F^2+28F+100

We move all terms to the left:

(F)-(2F^2+28F+100)=0

We get rid of parentheses

-2F^2+F-28F-100=0

We add all the numbers together, and all the variables

-2F^2-27F-100=0

a = -2; b = -27; c = -100;
Δ = b2-4ac
Δ = -272-4·(-2)·(-100)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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